Page 118 - Threading_Handbook
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2.12  Depth per Pass and Number of Passes
      THREAD TURNING  In order to produce threads, the cutting tool needs to make several numbers of cuts along



                  the workpiece surface. The parameters of depth per pass and number of passes have a
                  very important role in threading production. These parameters have a direct effect on cutting
                  edge wear, tool life, threading surface quality, and threading production stability.
                  The two methods most common in determining the depth per pass and the number of
                  passes are constant chip area by decreasing depth per pass or constant depth per pass.
                  The choice of method does not depend on the selected infeed methods (radial infeed, flank
                  infeed, modified flank infeed, alternating flank infeed), which are described in chapter 2.12.
                  The depth per pass and number of passes parameters depend on the type of equipment,
                  tool overhang, machine stability, workpiece material, cutter geometry and the threading
                  depth required.


                  Constant Chip Area by Decreasing Depth per Pass
                  (Recommended)


                  This is the most common method and is generally recommended, as in most cases it
                  ensures high productivity. The principle of this method is that the initial cutting depth at
                  the first pass is the largest, and then gradually decreases at each pass to ensure material
                  removal within a constant chip area. The calculation of passes is designed so that the last
                  pass, which is destined to be a finish pass, will be 0.05 - 0.1 mm (0.0019 - 0.0039 inches).
                  Using this method ensures constant loads on cutting edge and uniform wear,
                  which increases tool life.


























                  Formula for Calculation of Depth per Pass

                  ∆ap(i) =       ap   × √C
                          √n -1
                             a
                  When:
                  ∆ap(i)   — Depth of cut i pass (i = 1...na)
                  i        — Pass

                  ap       — Total depth of cut
                  na       — Number of passes

                  C        — Constant value:
                                                         nd
                                                                             rd
                                   st
   118    ISCAR               For 1  pass: C=0.3; For 2  pass: C=1; For 3  pass and higher: C = i − 1
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